一、题目
$$
I = \int_{0}^{\frac{\pi}{4}} \mathrm{~d} \theta \int_{0}^{\frac{1}{\cos \theta}} r^{2} \mathrm{~d} r+\int_{1}^{\sqrt{2}} \mathrm{~d} x \int_{0}^{\sqrt{2-x^{2}}} \sqrt{x^{2}+y^{2}} \mathrm{~d} y=?
$$
难度评级:
继续阅读“二重积分先定积分区域:但二重积分的值可不是积分区域的面积”