问题
若平面过点 $(x_{0}, y_{0}, z_{0})$, 且平面的法向量为 $\vec{n}$ $=$ $(A, B, C)$, 则空间直角坐标系下平面方程的 [点法式] 如何表示？选项
[A]. $A$ $(x – x_{0})$ $-$ $B$ $(y – y_{0})$ $-$ $C$ $(z – z_{0})$ $=$ $0$[B]. $A$ $(x \div x_{0})$ $+$ $B$ $(y \div y_{0})$ $+$ $C$ $(z \div z_{0})$ $=$ $0$
[C]. $A$ $(x + x_{0})$ $+$ $B$ $(y + y_{0})$ $+$ $C$ $(z + z_{0})$ $=$ $0$
[D]. $A$ $(x – x_{0})$ $+$ $B$ $(y – y_{0})$ $+$ $C$ $(z – z_{0})$ $=$ $0$
$\textcolor{red}{A}$ $\cdot$ $(\textcolor{cyan}{x} – \textcolor{orange}{x_{0}})$ $+$ $\textcolor{red}{B}$ $\cdot$ $(\textcolor{cyan}{y} – \textcolor{orange}{y_{0}})$ $+$ $\textcolor{red}{C}$ $\cdot$ $(\textcolor{cyan}{z} – \textcolor{orange}{z_{0}})$ $=$ $0$