2011年考研数二第04题解析

题目

微分方程 $y^{”} – \lambda^{2}y = e^{\lambda x} + e^{- \lambda x} (\lambda > 0)$ 的特解形式为 $?$

$$
A. a (e^{\lambda x} + e^{- \lambda x})
$$

$$
B. ax (e^{\lambda x} + e^{- \lambda x})
$$

$$
C. x (ae^{\lambda x} + be^{- \lambda x})
$$

$$
D. x^{2} (ae^{\lambda x} + be^{- \lambda x})
$$

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